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-1-9p^2=-55
We move all terms to the left:
-1-9p^2-(-55)=0
We add all the numbers together, and all the variables
-9p^2+54=0
a = -9; b = 0; c = +54;
Δ = b2-4ac
Δ = 02-4·(-9)·54
Δ = 1944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1944}=\sqrt{324*6}=\sqrt{324}*\sqrt{6}=18\sqrt{6}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18\sqrt{6}}{2*-9}=\frac{0-18\sqrt{6}}{-18} =-\frac{18\sqrt{6}}{-18} =-\frac{\sqrt{6}}{-1} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18\sqrt{6}}{2*-9}=\frac{0+18\sqrt{6}}{-18} =\frac{18\sqrt{6}}{-18} =\frac{\sqrt{6}}{-1} $
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